Assume efficiency ( \eta = 0.92 ): ( T = (1098.1 \times 75) / (2000 \times 0.92) = 44.76 ) Nm
You need a linear actuator to move a 500 kg load horizontally at 0.5 m/s with an acceleration of 2 m/s². Pinion module = 3, teeth = 25. rack and pinion calculations pdf
( F_total = F_inertia + F_friction ) Assume steel on steel rolling friction coefficient ( \mu = 0.02 ): ( F_friction = 500 \times 9.81 \times 0.02 = 98.1 ) N ( F_inertia = 500 \times 2 = 1000 ) N ( F_total = 1098.1 ) N Assume efficiency ( \eta = 0
However, the success of any engineering project hinges on accurate data. ( v = 0
( v = 0.5 ) m/s = 500 mm/s Travel per revolution = ( \pi \times 75 = 235.62 ) mm ( RPM = (500 / 235.62) \times 60 = 127.3 ) RPM